TN TET 2019 Paper 2 Math and Science Paper

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Question : 92 of 150

Marks: +1, -0

Find the sum of n terms of the series 6+66+666+........

S_n= $\;{3}/{2}$ $[\;{10(10^{n}−1)}/{9}−n]$
S_n= $\;{2}/{3}$ $[\;{10(10^{n}−1)}/{9}−n]$
S_n= $\;{2}/{3} [\;{10(10^{n}−1)}/{9}−n]$
S_n= $\;{1}/{3} [\;{10(10^{n}−1)}/{9}−n^{2}]$

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