Time and Work Practice Test 5 with solutions

Let time taken by A = (x) days
Time taken by B = (2x) days
Time taken by C = $\frac{\left(3\mathit{x}\right)}{2}$ days
Work done by A, B and C in one day
= $\frac{1}{\mathit{x}}+\frac{1}{2\mathit{x}}+\frac{2}{3\mathit{x}}$
= $\frac{6+3+4}{6\mathit{x}}$ = $\frac{13}{6\mathit{x}}$
Now $\frac{13}{6\mathit{x}}$ = $\frac{1}{18}$
⇒ x = 39
So, A will take 39 days.
B will take 78 days.
C will take $\frac{117}{2}$ = $58\frac{1}{2}$ days .