Time and Work Practice Test 5 with solutions

Both men's 3 day's work = $3\left(\frac{1}{7}+\frac{1}{8}\right)$ = $3\times \frac{15}{56}$ = $\frac{45}{56}$
Remaining work = 1 $-\frac{45}{56}$ = $\frac{11}{56}$
Ratio of their work done = $\frac{3}{7}:\frac{3}{8}:\frac{11}{56}$ = 24 : 21 : 11
Share of money of first man = $\frac{24}{24+21+11}\times \mathit{R}\mathit{s}.1400$
= $\frac{24}{56}\times \mathit{R}\mathit{s}.1400$
= Rs. 600
Share of money of second man = $\frac{21}{56}$ × Rs. 1400
= Rs. 525
Share of money of the boy = $\frac{11}{56}$ × Rs. 1400 = Rs. 275
Hence, their share will be Rs. 600, Rs. 525, Rs. 275.