Time and Work Practice Test 4 with solutions

Work done by A, B and C in one day
= $\frac{1}{13}+\frac{1}{26}+\frac{2}{39}$ = $\frac{6+3+4}{78}$
= $\frac{13}{78}$ = $\frac{1}{6}$
Work done by A, B and C in 5 days = $\frac{5}{6}$
Remaining work = $\frac{1}{6}$ , i.e., done by A alone
Days taken by A to complete the work = 13 days
Days taken by A to $\frac{1}{6}$ th part of the work = $\frac{13}{6}$ = $2\frac{1}{6}$ days
So, total time taken by A, B and C = 5 + 2 $\frac{1}{6}$
= $7\frac{1}{6}$ days