Time and Work Practice Test 3 with solutions

Work done by A, B and C in 3 days
= $3\left(\frac{1}{10}+\frac{1}{15}+\frac{1}{18}\right)$ = $3\left(\frac{9+6+5}{90}\right)$
= 3 × $\frac{20}{90}$ = $\frac{2}{3}$
Remaining work = 1 - $\frac{2}{3}$ = $\frac{1}{3}$
‘C’ can complete the work in 18 days.
$\frac{1}{3}$ rd part of work can be done in 18 × $\frac{1}{3}$ = 6 days.
So, ‘C’ completes the remaining work in 6 days.