Time and Work Practice Test 2 with solutions

Number of days taken by A can do 20% work = 13 days
So, Number of days taken by A
= $13\times 20\times 100$ = 65 days
Number of days taken by B to complete $\frac{6}{7}$ th part of work = 48 days.
So, work can be completed by B in
= $48\times \frac{7}{6}$ = 56 days
Number of days taken by C to complete $66\frac{2}{3}\%$ work = 42 days
So, number of days taken by C to complete the work
= $42\times \frac{3}{200}\times 100$ = 63 days
So, B is the most efficient worker among A, B and C.