Time and Work Practice Test 1 with solutions

Work done by A, B and C in one day
= $\frac{1}{8}+\frac{1}{6}+\frac{1}{10}$ = $\frac{23}{80}$
Work done by A, B and C in 2 days
= $2\times \frac{23}{80}$ = $\frac{46}{80}$
Work left = $1-\frac{46}{80}$ = $\frac{34}{80}$
Work done by B and C in one day
= $\frac{1}{16}+\frac{1}{10}$ = $\frac{13}{80}$
Work done by B and C in 2 days = $2\times \frac{13}{80}$ = $\frac{26}{80}$
Work left = $\frac{34}{80}-\frac{26}{80}$ = $\frac{8}{80}$ = $\frac{1}{10}$
$\frac{1}{10}$ work will be done by C in 1 day.
So, time taken to finish the work = 2 + 2 + 1 = 5 days.