Time and Distance Practice Test 4 with solutions

Question : 30 of 38

Marks: +1, -0

Two points A and B are 150 km apart. A man completes his onward journey from A to B in 3 hours 20 minutes and return journey from B to A in 4 hours 10 minutes. His average speed during the entire journey will be less than his average speed during the journey from A to B by :

5 km/h
7.5 km/h
9 km/h
3 km/h

Validate

Solution:

During onward journey from A to B:
Average speed =

{150}/{{10}/3}

{150×3}/{10}

= 45 km/hr.
During entire jouney :
Average speed =

{300}/{{10}/3+{25}/6}

{300×6}/{45}

= 40 km/hr.
Hence, difference of average speed = 45 – 40 = 5 km/hr

Go to Question:

Prev Question

Next Question