Time and Distance Practice Test 4 with solutions

The monkey climbs 12 metres in 1 minute and then he slips back 3 metres in the next minute
∴ The monkey climbs in the first 2 minutes = 12 – 3 = 9 metres
∴ In the first 12 minutes the monkey climbs = 9 × 6 = 54 metres
Remaining height of the pole to be covered by the monkey = 63 – 54 = 9 metre
∴ The monkey will climb the height of 9 metres in the 13th minute
∴ The monkey climbs 12 metres in 1 minute
∴ The monkey will climb 9 metres in $\frac{1}{12}\times 9$ = $\frac{3}{4}$ minute
∴ Time spent in climbing at the top of the pole = $\left(12+\frac{3}{4}\right)$ minutes = $12\frac{3}{4}$ minutes