Time and Distance Practice Test 2 with solutions

When speed is 5 km/hr, then the man reaches office late by 6 minutes.
= $\frac{6}{60}$ = $\frac{1}{10}$ hrs
When speed is 6 km/hr, then the man reaches office early by $\frac{2}{60}$ = $\frac{1}{30}$ hrs
Distance = $5\times 6\frac{\left(\frac{1}{10}+\frac{1}{30}\right)}{\left(6-5\right)}$
= $30\frac{\left(\frac{3+1}{30}\right)}{1}$
= $30\times \frac{4}{30}$ = 4 kms