Time and Distance Practice Test 1 with solutions

Distance covered by the thief in 24 minutes
= $20\times \frac{24}{60}$
= 8 km
Let the further distance covered by the thief = x km
So, the total distance covered by the police = x + 8
$\frac{\mathit{x}+8}{25}$ = $\frac{\mathit{x}}{20}$
20x + 160 = 25x
5x = 160
x = 32 km
Total time taken by the police = $\frac{32+8}{25}$ = 1 hour 36 minutes
Hence the thief will be caught at 2.24 a.m. + 1 hour 36 minutes = 4 a.m.