Find the points of inflexion of the normal curve. f(x)=\frac{1}{4 \sqrt{2 \pi} \cdot e^{\frac{-(x-10)^{2}}{32}} for -\alpha

Theoretical Distribution

Question : 96 of 118

Marks: +1, -0

Find the points of inflexion of the normal curve.

f(x)=\;{1}/{4 √{2 π}} ⋅ e^{\;{-(x-10)^{2}}/{32}}

for

-α < x < α

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