Simple Harmonic Motion

Section: Physics

Question : 4 of 5

Marks: +1, -0

A particle of mass 4 mg is executing simple harmonic motion along x -axis with an angular frequency of 40‌rad‌ s−1. If the potential energy of the particle is V(x)=a+bx2, where V(x) is in joule and x is in metre, then the value of b is

[TG EAPCET 9 May 2024 Shift 2]

‌800×10−6Jm−2
‌1600×10−6Jm−2
‌3200×10−6Jm−2
‌6400×10−6Jm−2

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