If \overline{a}=\overline{i}-\overline{j}+3 \overline{k}, \overline{c}=-\overline{k} are position vectors of two points and \overline{b}=2 \overline{i}-\overline{j}+\lambda \overline{k}, \overline{d}=\overline{i}+2 \overline{j}-\overline{k} are two vectors, then the lines \overline{r}=\overline{a}+t \overline{b}, \overline{r}=\overline{c}+s \overline{d} are [TG EAPCET 10 May 2024 Shift 2]

Correct Answer is : skew lines when λ≠193

skew lines when \lambda=\frac{19}{3}

coplanar \forall \lambda \in \mathbb{R}

skew lines when \lambda \neq \frac{19}{3}

coplanar when \lambda \neq \frac{19}{3}

Vector Algebra

Section: Mathematics

Question : 6 of 22

Marks: +1, -0

If a=i−j+3k,c=−k are position vectors of two points and b=2i−j+λk, d=i+2j−k are two vectors, then the lines r=a+tb,r=c+sd are

[TG EAPCET 10 May 2024 Shift 2]

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