Limits Continuity and Differentiability

Section: Mathematics

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Question : 2 of 15

Marks: +1, -0

lim

x⟶3∕2

‌

(4x2−6x)(4x2+6x+9)

‌3√2x−‌3√3

=

[TG EAPCET 11 May 2024 Shift 1]

‌3√317
‌‌3√316
‌‌3√315
‌‌3√314

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