Limits Continuity and Differentiability

Section: Mathematics

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Question : 14 of 15

Marks: +1, -0

lim

n⟶∞

[(1+‌

1

n2

)(1+‌

4

n2

)(1+‌

9

n2

)...(2)]1∕n=

[TG EAPCET 9 May 2024 Shift 1]

‌16e−1
‌2e(‌
π−4
2
)
‌2‌log‌2−1
‌2+e(‌
π−4
2
)

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