\int \sqrt{4 \cos ^2 x-5 \sin ^2 x} \cos x \dx= [TG EAPCET 10 May 2024 Shift 1]

Correct Answer is : 12sinx√4−9sin2x+23Sin−1(3sinx2)+c

\frac{1}{2} \cos x \sqrt{4-9 \sin ^2 x}+\frac{2}{3} {\Sin}^{-1} (\frac{3 \sin x}{2}) + {\c}

\frac{1}{2} \sin x \sqrt{4-9 \sin ^2 x}+\frac{2}{3} {\Cos}^{-1} (\frac{3 \cos x}{2}) + {\c}

\frac{1}{2} \cos x \sqrt{1-9 \cos ^2 x}+\frac{2}{3} {\Sin}^{-1} (\frac{3 \cos x}{2}) + {\c}

\frac{1}{2} \sin x \sqrt{4-9 \sin ^2 x}+\frac{2}{3} {\Sin}^{-1} (\frac{3 \sin x}{2}) + {\c}

Indefinite Integration

Section: Mathematics

Question : 13 of 22

Marks: +1, -0

∫√4cos2x−5sin‌2x‌cos‌x‌dx=

[TG EAPCET 10 May 2024 Shift 1]

Go to Question:

Prev Question

Next Question