\int(\log x)^3 \dx= [TG EAPCET 10 May 2024 Shift 1]

Correct Answer is : x[(logx)3−3(logx)2+6(logx)−6]+c

(\log x)^3-3(\log x)^2+6 \log x-6+c

x [(\log x)^3-3(\log x)^2+6(\log x)-6] + {\c}

(x \log x)^3-3(x \log x)^2+6 x(\log x)-6+ {\c}

\frac{1}{x} [(\log x)^3-3(\log x)^2+6 \log x-6] + {\c}

Indefinite Integration

Section: Mathematics

Question : 11 of 22

Marks: +1, -0

∫(log‌x)3‌dx=

[TG EAPCET 10 May 2024 Shift 1]

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