The equation that is satisfied by the general solution of the equation 4-3 \cos ^2 \theta=5 \sin \theta \cos \theta is [TG EAPCET 10 May 2024 Shift 1]

Correct Answer is : 1+sin2θ=3cos2θ

7 \sin ^2 \theta+3 \cos ^2 \theta=4

\sin ^2 \theta-2 \cos \theta+\frac{1}{4}=0

\cot \theta-\tan \theta= \sec \theta

1+ \sin ^2 \theta=3 \cos ^2 \theta

Trigonometric Equations

Section: Mathematics

Question : 3 of 7

Marks: +1, -0

The equation that is satisfied by the general solution of the equation 4−3cos2θ=5sin‌θ‌cos‌θ is

[TG EAPCET 10 May 2024 Shift 1]

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