{\L} \equiv x \cos \alpha+y \sin \alpha-p=0 represents a line perpendicular to the line x+y+1=0. If p is positive, \alpha lies in the fourth quadrant and perpendicular distance from (\sqrt{2}, \sqrt{2}) to the line {\L}=0 is 5 units then {\p}= [TG EAPCET 9 May 2024 Shift 2]

Straight Lines and Pair of Straight Lines

Section: Mathematics

Question : 20 of 26

Marks: +1, -0

L≡x‌cos‌α+ysin‌α−p=0 represents a line perpendicular to the line x+y+1=0. If p is positive, α lies in the fourth quadrant and perpendicular distance from (√2,√2) to the line L=0 is 5 units then p=

[TG EAPCET 9 May 2024 Shift 2]

5
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5
2
10
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15
2

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