{\S}^{'} is the focus of the ellipse \frac{x^2}{25}+\frac{y^2}{b^2}=1,(b< 5) lying on the negative X -axis and {\P}(\theta) is a point on this ellipse. If the distance between the foci of this ellipse is 8 and {\S}^{'} {\P}=7, then \theta= [TG EAPCET 10 May 2024 Shift 1]

Ellipse

Section: Mathematics

Question : 8 of 11

Marks: +1, -0

S′ is the focus of the ellipse ‌

+‌

=1,(b<5) lying on the negative X -axis and P(θ) is a point on this ellipse. If the distance between the foci of this ellipse is 8 and S′P=7, then θ=

[TG EAPCET 10 May 2024 Shift 1]

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