An element with molar mass 2.7 \times 10^{-2} {\kg} {\mol}^{-1} forms a cubic unit cell with edge length of 405 pm . If its density is 2.7 \times 10^3 {\kg} {\m}^{-3}, the number of atoms present in one unit cell of it is (Given; {\N}_{ {\A}}=6.023 \times 10^{23} {\mol}^{-1} ) [TG EAPCET 10 May 2024 Shift 1]

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An element with molar mass 2.7×10−2‌kg‌mol−1 forms a cubic unit cell with edge length of 405 pm . If its density is 2.7×103‌kg‌m−3, the number of atoms present in one unit cell of it is
(Given; NA=6.023×1023mol−1 )

[TG EAPCET 10 May 2024 Shift 1]

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