TG EAMCET 4 May 2025 Shift 2 Paper
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Question : 90 of 160
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The force ( F in newton) acting on a particle of mass 90 g executing simple harmonic motion is given by F + 0.04 π 2 y = 0 , where y is displacement of the particle in meter.
If the amplitude of the particle is
m , then the maximum velocity of the particle is
If the amplitude of the particle is
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