The vertical displacement ( y in metre) of a projectile in terms of its horizontal displacement ( x in metre) is given by y= (\sqrt{3} x-0.2 x^2). The time of flight of the projectile is (Acceleration due to gravity =10 {\ms}^{-2} )

TG EAMCET 4 May 2025 Shift 2 Paper

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The vertical displacement ( y in metre) of a projectile in terms of its horizontal displacement ( x in metre) is given by y=(√3x−0.2x2). The time of flight of the projectile is
(Acceleration due to gravity =10ms−2 )

‌5√3 s
‌√3 s
‌0.2 s
‌0.2√3 s

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