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Question : 74 of 160
Marks:
+1,
-0
Solution:
‌3x+2=α⋅‌(4x2+4x+5)+β‌3x+2=(8x+4)α+β‌⇒3=8α‌ and ‌4α+β=2‌⇒α=‌‌ and ‌β=2−‌=‌‌‌ Let ‌I=∫‌‌dx‌=‌‌log(4x2+4x+5)+‌‌∫‌‌=‌‌log(4x2+4x+5)+‌×‌×tan−1(‌)+C‌⇒A+B=‌+‌=‌
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