TG EAMCET 4 May 2025 Shift 2 Paper

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Question : 5 of 160

Marks: +1, -0

If A=[

0	1	2
1	2	3
3	x	1

],A−1=‌

1

2

[

1	−1	1
−8	6	2y
5	−3	1

] then the point (x,y) lies on the curve represented by the equation

‌y=3x2−5x−1
‌y=log2∕5(2x+2−x)
‌y=‌
ex+1
ex−1
‌3x2y−5xy+12=0

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