In a quadrilateral {\ABCD}, ⌊ {\A}=\frac{2 \pi}{3}. and AC is the bisector of angle ⌊ {\A}. If 15|\overline{ {\AC}}|=5|\overline{ {\AD}}|=3|\overline{ {\AB}}|, then angle between \overline{ {\AB}} and \overline{ {\BC}} is

Correct Answer is : Cos−1(3√32√7)

{\Cos}^{-1} ( {\sqrt{3}}/{\sqrt{7}})

{\Cos}^{-1} ( {3 \sqrt{3}}/{2 \sqrt{7}})

{\Cos}^{-1} ( {4 \sqrt{3}}/{5 \sqrt{7}})

{\Cos}^{-1} ( {3 \sqrt{3}}/{4 \sqrt{7}})

TG EAMCET 4 May 2025 Shift 2 Paper

Question : 32 of 160

Marks: +1, -0

In a quadrilateral ABCD,⌊A=‌

2π

. and AC is the bisector of angle ⌊A. If 15|AC|=5|AD|=3|AB|, then angle between AB and BC is

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