Numerically greatest term in the expansion of (3 x-4 y)^{23} when x=\frac{1}{6} and y=\frac{1}{8} is

Correct Answer is : 23C11(12)23

{ }^{23} {\C}_{11} (\frac{8}{6}) ^{23}

{ }^{23} {\C}_{11} (\frac{6}{8}) ^{23}

{ }^{23} {\C}_{11} (\frac{1}{2}) ^{23}

TG EAMCET 4 May 2025 Shift 2 Paper

Question : 19 of 160

Marks: +1, -0

Numerically greatest term in the expansion of (3x−4y)23 when x=‌

and y=‌

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