f(x)=x^2-2(4 {\K}-1) x+g( {\K})>0 \forall x \in \mathbb{R} and for {\K} \in( {\a}, {\b}). If g( {\K})=15 {\K}^2-2 {\K}-7, then

Correct Answer is : g(K) attains its maximum at the midpoint of (a,b)

g( {\K}) attains its maximum at the midpoint of ( {\a}, {\b})

g( {\K}) attains its minimum at two points in ( {\a}, {\b})

g( {\K}) attains its both maximum and minimum in ( {\a}, {\b})

g( {\K}) attains no maximum and no minimum in ( {\a}, {\b})

TG EAMCET 4 May 2025 Shift 2 Paper

Question : 12 of 160

Marks: +1, -0

f(x)=x2−2(4K−1)x+g(K)>0‌∀x∈ℝ and for K∈(a,b). If g(K)=15K2−2K−7, then

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