If the electric field of a plane electromagnetic wave is {\E}_z=60 \sin (0.5 \times 10^3 x+1.5 \times 10^{11} {\t}) {\Vm}^{-1}, then the magnetic field of the wave is

Correct Answer is : By=2×10−7sin(0.5×103x+1.5×1011t)T

B_y=2 \times 10^{-7} \sin (0.5 \times 10^3 x+1.5 \times 10^{11} {\t}) {\T}

B_z=2 \times 10^{-7} \sin (0.5 \times 10^3 x+1.5 \times 10^{11} {\t}) {\T}

B_x=180 \times 10^8 \sin (0.5 \times 10^3 x+1.5 \times 10^{11} {\t}) {\T}

B_y=180 \times 10^8 \sin (0.5 \times 10^3 x+1.5 \times 10^{11} {\t}) {\T}

TG EAMCET 4 May 2025 Shift 2 Paper

Question : 113 of 160

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If the electric field of a plane electromagnetic wave is Ez=60sin‌(0.5×103x+1.5×1011t)Vm−1, then the magnetic field of the wave is

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