TG EAMCET 4 May 2025 Shift 2 Paper

A proton moving with a velocity of 8×105ms−1 enters a uniform magnetic field normal to the direction of the magnetic field. If the radius of the circular path of the proton in the magnetic field is 8.3 cm , then the magnitude of the magnetic field is (Charge of proton =1.6×10−19C and mass of the proton =1.66×10−27‌kg )