TG EAMCET 4 May 2025 Shift 1 Paper

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Question : 80 of 160

Marks: +1, -0

The differential equation corresponding to the family of ellipses ‌

x2

a2

+‌

y2

4

=1, where ' a ' is an arbitrary constant is

xy‌
dy
dx
=4−y2
xy‌
dy
dx
=4−x2
xy‌
dy
dx
=x2−4
xy‌
dy
dx
=y2−4

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