If I_1=\int \sin ^6 x \dx and I_2=\int \cos ^6 x \dx, then I_1+I_2=

Correct Answer is : 132(20x+3sin4x)+C

\frac{5 x}{8}+\frac{3 \cos 4 x}{32}+C

\frac{1}{32}(20 x-3 \sin 4 x)+C

\frac{1}{32}(20 x+3 \sin 4 x)+C

\frac{5 x}{4}+\frac{3 \sin 4 x}{16}+C

TG EAMCET 4 May 2025 Shift 1 Paper

Question : 73 of 160

Marks: +1, -0

If I1=∫sin‌6x‌dx and I2=∫cos6x‌dx, then I1+I2=

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