TG EAMCET 4 May 2025 Shift 1 Paper

Let direction ratio of normal line of plane π1 be (a,−1,3).
Let direction ratio of normal line of plane π2 be (3,a,1)
‌cos‌60∘=‌

3a−a+3

√a2+10×√a2+10

=‌

2a+3

a2+10

‌⇒‌‌‌

1

2

=‌

2a+3

a2+10

⇒a2+10=4a+6
‌⇒‌‌a2−4a+4=0⇒a=2
⇒ Direction ratio of line perpendicular to the plane (a+2)x+(a−4)y+2az=a will be (a+2):(a−4):(2a)
4:−2:4
Direction ratio 2 : −1:2