TG EAMCET 4 May 2025 Shift 1 Paper

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Question : 4 of 160
 
Marks: +1, -0
If x=α,y=β,z=γ is the solution of the system of equations 2x+3y+z=−1,3x+y+z=4,x−3y−2z=1, then the value of β is
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