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Question : 10 of 160
Marks:
+1,
-0
Solution:
‌(1−i√3)2025‌⇒1−i√3=2(cos(−‌)+isin‌(−‌))‌‌=2e−iπ∕3⇒(1−i√3)2025=22025e−i675π=‌22025(cos‌675‌π−isin‌675π‌=−22025
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