TG EAMCET 3 May 2025 Shift 2 Paper

Step 1: Find the acceleration
We know the final speed v=18m∕s, the starting speed u=0, and the height h=20m.
Use the formula: v2=u2+2ah
Put the values in: 182=02+2a×20
This gives: a=‌

18×18

2×20

=8.1m∕s2
Step 2: Find the time taken
Use the formula: v=u+at
Plug in the numbers: 18=0+8.1×t
Solve for t :
t=‌

18

8.1

=2.22s≈2.2s