If x= \sin 2 \theta \cos 3 \theta, y= \sin 3 \theta \cos 2 \theta, then \frac{d y}{d x}=

Correct Answer is : 2cos5θ+cos3θcos2θ2cos5θ−sin3θsin2θ

\frac{2 \cos 5 \theta+ \sin 3 \theta \sin 2 \theta}{2 \cos 5 \theta-\cos 3 \theta \cos 2 \theta}

\frac{2 \cos 5 \theta- \sin 3 \theta \sin 2 \theta}{2 \cos 5 \theta+\cos 3 \theta \cos 2 \theta}

\frac{2 \cos 5 \theta+\cos 3 \theta \cos 2 \theta}{2 \cos 5 \theta- \sin 3 \theta \sin 2 \theta}

\frac{2 \cos 5 \theta- \sin 3 \theta \sin 2 \theta}{2 \cos 5 \theta-\cos 3 \theta \cos 2 \theta}

TG EAMCET 3 May 2025 Shift 2 Paper

Question : 66 of 160

Marks: +1, -0

If x=sin‌2θ‌cos‌3‌θ,y=sin‌3θ‌cos‌2‌θ, then ‌

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