Let {\P}, {\Q}, {\R}, {\S} be the points of intersection of the circle x^2+y^2=4 and the hyperbola x y=\sqrt{3}. If P=(\alpha, \beta) and \alpha>\beta>0, then the equation of the tangent drawn at P to the hyperbola is

Correct Answer is : x+√3y=2√3

TG EAMCET 3 May 2025 Shift 2 Paper

Question : 57 of 160

Marks: +1, -0

Let P,Q,R,S be the points of intersection of the circle x2+y2=4 and the hyperbola xy=√3. If P=(α,β) and α>β>0, then the equation of the tangent drawn at P to the hyperbola is

‌x+y=2
‌x+√3y=2√3
‌√3x+y=√3
‌x−y=0

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