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Question : 27 of 160
Marks:
+1,
-0
Solution:
‌coth2x−tanh2x‌=‌−‌‌=‌| (cosh2x+ sinh2x)(cosh2x− sinh2x) |
| sinh2xâ‹…cosh2x |
‌=‌| (cosh2x+ sinh2x) |
| sinh2xâ‹…cosh2x |
=‌| 4‌cosh‌2‌x |
| ( sinh2x)2 |
‌=4‌cosh‌2‌x(cosech‌2‌x)2
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