4 \cos \frac{7 \theta}{2} \cos \frac{3 \theta}{2} \sin 5 \theta=

Correct Answer is : sin10θ+sin7θ+sin3θ

\sin 10 \theta+ \sin 7 \theta- \sin 3 \theta

\sin 10 \theta+ \sin 7 \theta- \sin 5 \theta

\sin 10 \theta+ \sin 7 \theta+ \sin 3 \theta

\sin 10 \theta+ \sin 7 \theta+ \sin 5 \theta

TG EAMCET 3 May 2025 Shift 2 Paper

Question : 24 of 160

Marks: +1, -0

4‌cos‌

7θ

‌cos‌

3θ

sin‌5θ=

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