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Question : 10 of 160
Marks:
+1,
-0
Solution:
We have,
‌z=(√3+i)10+(√3−i)10‌=(2e‌)10+(2e‌)10‌=210(e‌+e‌)‌=210(cos‌+isin‌‌+cos‌−isin‌‌)‌=210⋅2‌cos‌=211‌cos(2π−‌)‌=211×‌=210=1024
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