TG EAMCET 3 May 2025 Shift 1 Paper

Step 1: Find Surface Area Relationship
The bubble's surface area at the top is 125% more than at the bottom. This means:
A‌top ‌=A‌bottom ‌+1.25A‌bottom ‌=2.25A‌bottom ‌
Step 2: Connect Surface Area and Volume
The volume (V) of a bubble is related to its surface area (A) by: V∝A3∕2
Step 3: Express Volume Change
Let V1 be the volume at the bottom, and V2 at the top. Then,
‌

V2

V1

=(‌

A2

A1

)3∕2=(2.25)3∕2=3.375
Step 4: Use Boyle's Law for Pressure and Volume
Since the water temperature is the same, Boyle's law applies: p1V1=p2V2‌

p1

p2

=‌

V2

V1

=3.375
Step 5: Write Out Pressure at Bottom and Top
At the bottom, pressure is p1= atmospheric pressure + pressure from water column with height h Atmospheric pressure is equal to water pressure from 10 m column. So: p1=10+h At the top, the pressure is just the atmospheric pressure: p2=10
Step 6: Set Up the Equation and Solve for h
So, ‌

p1

p2

=‌

10+h

10

Set equal to 3.375:‌

10+h

10

=3.37510+h=33.75h=23.75m