\int \frac{\log x}{(1+x)^3} \dx=

Correct Answer is : 12[11+x−logx(1+x)2+log(x1+x)]+C

\frac{1}{2} [\frac{1}{1+x}+\frac{\log x}{(1+x)^2}-\log (x^2+x) ] +C

\frac{1}{2} [\frac{1}{1+x}-\frac{\log x}{(1+x)}-\log (1+x^2) ] +C

\frac{1}{2} [\frac{1}{1+x}+\frac{\log x}{(1+x)^2}-\log (1+x^2) ] +C

\frac{1}{2} [\frac{1}{1+x}-\frac{\log x}{(1+x)^2}+\log (\frac{x}{1+x}) ] +C

TG EAMCET 3 May 2025 Shift 1 Paper

Question : 75 of 160

Marks: +1, -0

∫‌

log‌x

(1+x)3

‌dx=

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