TG EAMCET 3 May 2025 Shift 1 Paper

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Question : 62 of 160

Marks: +1, -0

For a≠0 and b≠0, if the real valued function f(x)=‌

‌5√a(625+x)−5

‌4√625+bx−5

is continuous at x=0, then f(0)=

‌
4b
5
‌
5b
4
‌
5
4b
‌
4
5b

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