A bullet of mass ' m ' moving with a velocity ' u ' gets embedded in a block of mass ' M ' initially at rest. If ' \mu ' is the coefficient of friction between the block and the ground, then the displacement of the block due to the impact is

Correct Answer is : 12µg(muM+m)2

\frac{1}{2 \mu {\g}} ( { {\mu}}/{ {\M}}) ^2

\frac{1}{2 \mu {\g}} ( { {\mu}}/{ {\M}+ {\m}}) ^2

{( {\mu})^2}/{2 \mu( {\M}+ {\m}) {\g}}

TG EAMCET 29 Apr 2025 Shift 1 Paper

Question : 86 of 160

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A bullet of mass ' m ' moving with a velocity ' u ' gets embedded in a block of mass ' M ' initially at rest. If ' µ ' is the coefficient of friction between the block and the ground, then the displacement of the block due to the impact is

‌‌
1
2µg
(‌
mu
M
)2
‌‌
1
2µg
(‌
mu
M+m
)2
‌‌
(mu)2
2µ‌Mg
‌‌
(mu)2
2µ(M+m)g

Validate

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