A cannon on a cliff 55 m above the ground fires a shell with a velocity of 50 \stackrel{\^}{ {\i}}+50 \stackrel{\^}{ {\j}} {\ms}^{-1}. The displacement vector of the shell when it hits the ground is (Acceleration due to gravity =10 {\ms}^{-2} )

Correct Answer is : (550^i−55^j)m

(550 \stackrel{\^}{ {\i}}-55 \stackrel{\^}{ {\j}}) {\m}

(550 \stackrel{\^}{ {\i}}-500 \stackrel{\^}{ {\j}}) {\m}

(500 \stackrel{\^}{ {\i}}-55 \stackrel{\^}{ {\j}}) {\m}

(500 \stackrel{\^}{ {\i}}-550 \stackrel{\^}{ {\j}}) {\m}

TG EAMCET 29 Apr 2025 Shift 1 Paper

Question : 84 of 160

Marks: +1, -0

A cannon on a cliff 55 m above the ground fires a shell with a velocity of 50

+50

ms−1. The displacement vector of the shell when it hits the ground is (Acceleration due to gravity =10ms−2 )

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