TG EAMCET 2 May 2025 Shift 2 Paper

As object return with smaller speed that means there is a loss of energy. This loss of energy occurs due to viscous drag of atmosphere. While object is moving up let viscous drag produces an deceleration ' a '.
Then,
‌v2−u2=2as
⇒‌‌0−(10)2=2(−(g+a))h....(i)
‌ or ‌‌‌100=2(g+a)h
While coming down,
‌⇒‌‌64−0=2(−(g−a))(−h)
‌⇒‌‌64=2(g−a)h.....(ii)
Dividing (i) and (ii) we get
‌‌

100

64

=‌

g+a

g−a

⇒‌‌100g−100a=64g+64a
‌36g=164a‌ or ‌a=‌

36

164

g
Substituting ' a ' in either (i) or (ii) we get ' h.
From (ii)
‌64‌=2(g−‌

36

164

g)h
⇒‌32‌=(‌

164−36

164

)gh⇒
⇒‌h‌=4.1m