Two bodies are projected from the same point with the same initial velocity ' u ' making angles ' \theta^{'} and (90^{\circ}-\theta) with the horizontal in opposite directions. The horizontal distance between their positions when the bodies are at their maximum heights is

Correct Answer is : u2sin2(90∘−θ)g

\frac{u^2}{2 g} ( \sin ^2 \theta-\cos ^2 \theta)

\frac{u^2 \sin 2 (90^{\circ}-\theta) }{g}

TG EAMCET 2 May 2025 Shift 2 Paper

Question : 84 of 160

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Two bodies are projected from the same point with the same initial velocity ' u ' making angles ' θ′ and (90∘−θ) with the horizontal in opposite directions. The horizontal distance between their positions when the bodies are at their maximum heights is

‌
u2
2g
(sin‌2θ−cos2θ)
‌
u2sin‌2θ
2g
‌
u2
g
‌
u2sin‌2(90∘−θ)
g

Validate

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