TG EAMCET 2 May 2025 Shift 2 Paper

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Question : 76 of 160

Marks: +1, -0

lim

n⟶∞

‌

1

n2

[e1∕n+2e2∕n+3e3∕n+...+2ne2]=

e2−1
e2+1
2e2−2
2e2+1

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